The starter and exit quiz of the lesson “Finding the equation of the tangent to a circle”, from the unit “Real-life graphs” (Year 11 Maths) by Oak National Academy.
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Oak National Academy
12 questions
The tangent at any point on a circle __________ to the radius at that point.
What is the gradient of the line passing through the points (-7,-8) and (-9,10)?
What is the equation of the line passing through the points (8,11) and (-12,6)?
Match the centre of each circle to the equation for the circle.
What is the gradient of the radius connecting the centre of the circle (x-175)^2+(y+65)^2=250 to the point (190,-70) on the circumference?
What is the equation of the radius connecting the centre of the circle (x-5)^2+(y+8)^2=10 to the point (4,-5) on the circumference?
A tangent of a circle is a line that intersects the circle __________.
From the equation: (x-7)^2+(y-10)^2=25 we can deduce what?
The equation of a circle is (x-2)^2+(y-3)^2=80 Which of the below coordinate pairs will be on the radius connecting the centre of the circle to the point (6,11) on the circumference?
The gradient of the radius connecting a circle's centre to the point (4,11) is 4. What is the gradient of the tangent to the circle at this point?
The gradient of the radius connecting a circle's centre to the point (6,6) is -{1\over3}. What is the equation of the tangent to the circle at this point? Answer in the form y=mx+c
What is the equation of the tangent to the circle (x+15)^2+(y-8)^2=13 at the point (-13,5)?
